Input and Display the elements of Array in C programming

By directly defining the array size.

#include<stdio.h>

#include<conio.h>

main()

{

int arr[5],i;

printf("Enter the value for array:\n");

for(i=0;i<5;i++)

{

  scanf("%d",&arr[i]);

}

printf("\n");

printf("The array elements are :\n");

 for(i=0;i<5;i++)

 {

        printf("%d\n",arr[i]);

 }

  getch();

}

The output of the program:

 Note: In above program array size 5 is direrectly define by the user and five elements which are input by user stored in that elements.

By using constant value for array

#include<stdio.h>

#include<conio.h>

int main()

{

int i,num[5]= {3,56,76,5,90};

printf("List of array\n");

for(i=0;i<5;++i)

{

         printf("%d\t",num[i]);

}

getch();

}

The output of the program:

 Note: In above program size of the array is 5 already defined and elements are also fixed for that elements.

By inputting the size of the array from the user

#include <stdio.h>

#include <conio.h>

main()

{

int n, i;

printf("Enter the size of the arrays:\n");

scanf("%d", &n);

int arr[n];

printf("Enter %d the elements of the array:\n",n);

for (i=0; i<n; i++)

{

    scanf("%d", &arr[i]);

}

 printf("The array elements are:\n");

{

         for(i=0;i<n;i++)

         printf("%d\n",arr[i]);

}

getch();

}

The output of the program:

Note: In above program the size of the array is input by the user so on the basis of that array size can be declared and elements are stored on that.